2002 AMC 10B Problem 5

Attempt Problem 5 of the 2002 AMC 10B below, then check your answer against the professionally curated solution from LIVE by Po-Shen Loh. You can also try the full timed exam, view all 2002 AMC 10B solutions, or check the answer key.

All problems are used with official legal permission of the Mathematical Association of America (MAA).

5.

Circles of radius 22 and 33 are externally tangent and are circumscribed by a third circle, as shown in the figure. What is the area of the shaded region?

3π3\pi

4π4\pi

6π6\pi

9π9\pi

12π12\pi

Answer: E
Concepts:tangent circlescircle area
Difficulty rating: 1020
Solution:

The two small circles line up along a diameter of the big circle, so that diameter is 23+22=102\cdot3 + 2\cdot2 = 10 and the large radius is 5.5.

The shaded region is the large disk with the two small disks removed: π(52)π(32)π(22)=π(2594)=12π. \begin{aligned} &\pi(5^2) - \pi(3^2) - \pi(2^2) \\ &= \pi(25 - 9 - 4) \\ &= 12\pi. \end{aligned}

Thus, the correct answer is E.

← Problem 4#4
Full Exam

Problem 5 in Other Years