2002 AMC 10A Problem 5

Attempt Problem 5 of the 2002 AMC 10A below, then check your answer against the professionally curated solution from LIVE by Po-Shen Loh. You can also try the full timed exam, view all 2002 AMC 10A solutions, or check the answer key.

All problems are used with official legal permission of the Mathematical Association of America (MAA).

5.

Each of the small circles in the figure has radius one. The innermost circle is tangent to the six circles that surround it, and each of those circles is tangent to the large circle and to its small-circle neighbors. Find the area of the shaded region.
π\pi
1.5π1.5\pi
2π2\pi
3π3\pi
3.5π3.5\pi
Answer: C
Concepts:tangent circlescircle area
Small hint:
The large radius spans the center circle plus two more radii
Big hint:
Subtract the seven unit circles from the large circle
Solution:
The center of a surrounding circle is 22 from the center (two radii), and adding its own radius 11 gives a large radius of 3.3.
The large circle has area 9π,9\pi, and the seven unit circles have total area 7π,7\pi, so the shaded region is 9π−7π=2π.9\pi-7\pi=2\pi.
Thus, the correct answer is C.
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