2002 AMC 10A Problem 18

Attempt Problem 18 of the 2002 AMC 10A below, then check your answer against the professionally curated solution from LIVE by Po-Shen Loh. You can also try the full timed exam, view all 2002 AMC 10A solutions, or check the answer key.

All problems are used with official legal permission of the Mathematical Association of America (MAA).

18.

A 3×3×33\times 3\times 3 cube is formed by gluing together 2727 standard cubical dice. (On a standard die, the sum of the numbers on any pair of opposite faces is 7.7.) The smallest possible sum of all the numbers showing on the surface of the 3×3×33\times 3\times 3 cube is

6060

7272

8484

9090

9696

Answer: D
Concepts:cube geometryoptimizationcasework
Difficulty rating: 1540
Solution:

The 88 corner dice show 33 faces each, minimized at 1+2+3=6,1+2+3=6, contributing 86=48.8\cdot 6=48. The 1212 edge dice show 22 faces, minimized at 1+2=3,1+2=3, contributing 123=36.12\cdot 3=36.

The 66 face-center dice show 11 face, minimized at 1,1, contributing 6,6, and the hidden interior die contributes 0.0. The total is 48+36+6=90.48+36+6=90.

Thus, the correct answer is D.

← Problem 17#17
Full Exam

Problem 18 in Other Years