2001 AMC 10 Problem 22

Attempt Problem 22 of the 2001 AMC 10 below, then check your answer against the professionally curated solution from LIVE by Po-Shen Loh. You can also try the full timed exam, view all 2001 AMC 10 solutions, or check the answer key.

All problems are used with official legal permission of the Mathematical Association of America (MAA).

22.

In the magic square shown, the sums of the numbers in each row, column, and diagonal are the same. Five of these numbers are represented by v,w,x,y,v, w, x, y, and z.z. Find y+z.y+z.

4343

4444

4545

4646

4747

Answer: D
Concepts:magic squarelinear equation
Difficulty rating: 1530
Solution:

Since vv sits in the first row, first column, and main diagonal, the remaining two entries of each of those lines have equal sums: 25+18=24+w=21+x.25+18=24+w=21+x. So w=19w=19 and x=22.x=22.

The anti-diagonal 25,22,1925, 22, 19 sums to 66,66, so the magic sum is 66.66. Then v=662419=23,v=66-24-19=23, y=661822=26,y=66-18-22=26, and z=662521=20.z=66-25-21=20.

Hence y+z=46.y+z=46. Thus, the correct answer is D.

← Problem 21#21
Full Exam

Problem 22 in Other Years