2000 AMC 10 Problem 12

Attempt Problem 12 of the 2000 AMC 10 below, then check your answer against the professionally curated solution from LIVE by Po-Shen Loh. You can also try the full timed exam, view all 2000 AMC 10 solutions, or check the answer key.

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12.

Figures 0,1,2,0, 1, 2, and 33 consist of 1,5,13,1, 5, 13, and 2525 nonoverlapping unit squares, respectively. If the pattern were continued, how many nonoverlapping unit squares would there be in figure 100?100?

1040110401

1980119801

2020120201

3980139801

4080140801

Answer: C
Concepts:sum of first n odd numbersperfect squarepattern recognition
Difficulty rating: 1240
Solution:

Figure nn can be split into the sum of the first nn odd numbers and the first n+1n+1 odd numbers, giving n2+(n+1)2n^2 + (n+1)^2 unit squares.

For figure 100,100, this is 1002+1012=10000+10201=20201. \begin{aligned} 100^2 + 101^2 &= 10000 + 10201 \\ &= 20201. \end{aligned}

Thus, the correct answer is C.

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