2022 AMC 8 第 9 题

先试着解答 2022 AMC 8 第 9 题,然后核对你的答案与精心整理的解答,解答来自 LIVE by Po-Shen Loh。你也可以参加完整限时模拟考试、查看全部 2022 AMC 8 解答,或核对答案。

所有题目均经美国数学协会(MAA)官方合法授权使用。

9.

一杯沸水(212∘212^\circF)放在一个温度保持 68∘68^\circF 的房间中冷却。假设水温与室温的差每 55 分钟减半。1515 分钟后,水温是多少华氏度?
A cup of boiling water (212∘212^\circ F) is placed to cool in a room whose temperature remains constant at 68∘68^\circ F. Suppose the difference between the water temperature and the room temperature is halved every 55 minutes. What is the water temperature, in degrees Fahrenheit, after 1515 minutes?
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8686
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9898
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答案:B
知识点:等比数列
小提示:
跟踪水温与室温的差
Track the difference from room temperature
大提示:
1515 分钟内,这个差减半 33 次
In 1515 minutes, the difference is halved 33 times
解答:
当前水温和室温的差为 212−68=144212-68 = 144 。
1515 分钟包含三个 55 分钟,所以温差会减半 33 次。
也就是说温差乘以 (12)3=18(\dfrac{1}{2})^3 = \dfrac{1}{8} ,新的温差是 18⋅144=18\dfrac{1}{8}\cdot144=18。水温为 68+18=8668+18=86。
正确答案是 B。
The current difference is 212−68=144.212-68 = 144 .
Since we have 1515 minutes while halving every 55 minutes, we halve the difference 33 times.
This means the difference is multiplied by (12)3=18,(\dfrac{1}{2})^3 = \dfrac{1}{8} , so our new difference is 18⋅144=18.\dfrac{1}{8}\cdot144=18. This makes our final temperature 68+18=86.68+18=86.
Thus, the correct answer is B.
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