2022 AMC 8 第 23 题

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所有题目均经美国数学协会(MAA)官方合法授权使用。

23.

在一个 3×33 \times 3 网格的每个小方格中放入一个 \bigtriangleup\bigcirc。下面显示了一个有三个 \bigtriangleup 连成一线的示例。

有多少种配置同时有三个 \bigtriangleup 连成一线,并且有三个 \bigcirc 连成一线?

A \bigtriangleup or \bigcirc is placed in each of the nine squares in a 3×33 \times 3 grid. Shown below is a sample configuration with three \bigtriangleup's in a line.

How many configurations will have three \bigtriangleup's in a line and three \bigcirc's in a line?

3939

4242

7878

8484

9696

答案:D
知识点:分类讨论对称性
难度评级:1670
解答:

设三角形个数为 kk。要同时有三角形线和圆形线,必须有 3k63\le k\le6

k=3k=3,三角形必须成一条线。行或列共有 66 条可行;对角线不行,因为剩下的 66 个圆形中没有完整圆形线。所以 k=3k=3 时有这些配置。由对称性,k=6k=6 也有六种。

k=4k=4,先选一条三角形线。若这条线是行或列,额外的三角形有 66 个位置可选,共 66=366\cdot6=36 种;若这条线是对角线,则不能留下圆形线。由对称性,k=5k=5 也有 3636 种。

总数为 6+36+36+6=846+36+36+6=84

正确答案是 D

Let kk be the number of triangles. To have both a triangle line and a circle line, we need 3k63\le k\le6.

If k=3k=3, the three triangles must form a line. A row or column works, because the remaining six circles contain a full circle row or column. A diagonal does not work, because its complement contains no full line of circles. Thus there are 66 configurations for k=3k=3. By symmetry, there are also 66 configurations for k=6k=6.

If k=4k=4, choose the triangle line and then the extra triangle. If the line is a row or column, all 66 possible extra positions work, because one parallel row or column remains all circles. This gives 66=366\cdot6=36 configurations. If the triangle line is a diagonal, no extra position leaves a full circle line. By symmetry, k=5k=5 also gives 3636 configurations.

The total number of configurations is 6+36+36+6=846+36+36+6=84.

Thus, the correct answer is D.

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