2018 AMC 8 第 4 题

先试着解答 2018 AMC 8 第 4 题,然后核对你的答案与视频与精心整理的解答,解答来自 LIVE by Po-Shen Loh。你也可以参加完整限时模拟考试、查看全部 2018 AMC 8 解答,或核对答案。

所有题目均经美国数学协会(MAA)官方合法授权使用。

4.

图中的十二边形画在 1 cm×1 cm1 \text{ cm}\times 1 \text{ cm} 的方格纸上。该图形的面积是多少 cm2\text{cm}^2?
The twelve-sided figure shown has been drawn on 1 cm×1 cm1 \text{ cm}\times 1 \text{ cm} graph paper. What is the area of the figure in cm2?\text{cm}^2?
1212
12.512.5
1313
13.513.5
1414
答案:C
知识点:面积分割三角形面积
小提示:
可以把图形放进一个便于计算的长方形中,或者把它分成中间的正方形和周围的小三角形
Enclose the figure in an easy rectangle or split it into a central square and small triangles.
大提示:
斜边部分形成四个全等的直角三角形,每个面积为 11
The slanted parts form four congruent right triangles of area 11.
视频讲解:
解答视频缩略图
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文字解答:
如图所示,可以把图形分解:
现在可以看出,中间是一个 3×33 \times 3 正方形,周围有 44 个较小的阴影三角形。
正方形面积为 3⋅3=93 \cdot 3 = 9。每个小三角形的底为 22,高为 11,所以面积为 bh2=2⋅12=1。\dfrac{bh}{2} = \dfrac{2\cdot 1}{2} =1\text{。}这样的三角形有 44 个,所以它们的总面积为 1⋅4=41\cdot 4 = 4。
因此总面积是 9+4=139+4 = 13。
所以正确答案是 C。
To solve for the area of the figure, we separate the compound shape into parts that are easier to work with, as such:
As is now clear, there is the center 3×33 \times 3 square, with 44 smaller shaded triangles surrounding it.
The area of the square is 3⋅3=9.3 \cdot 3 = 9. The other triangles each have a base of 22 and a height of 1,1, so their area is equal to bh2=2⋅12=1.\dfrac{bh}{2} = \dfrac{2\cdot 1}{2} =1 . There are 44 of these triangles, so their total area is 1⋅4=4.1\cdot 4 = 4.
Therefore, the total area is 9+4=13.9+4 = 13.
Thus, the correct answer is C.
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