2017 AMC 8 第 10 题

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所有题目均经美国数学协会(MAA)官方合法授权使用。

10.

一个盒子中有五张卡片,编号为一、二、三、四、五。从盒中随机不放回地选出三张卡片。所选卡片中的最大值为四的概率是多少?

A box contains five cards, numbered 1, 2, 3, 4, and 5. Three cards are selected randomly without replacement from the box. What is the probability that 4 is the largest value selected?

110\dfrac{1}{10}

15\dfrac{1}{5}

310\dfrac{3}{10}

25\dfrac{2}{5}

12\dfrac{1}{2}

答案:C
知识点:基本概率组合
难度评级:1020
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文字解答:

选择 33 张卡从 55 张卡中共有 (53)=10{5 \choose 3} = 10 种方式。如果 44 是最大值,则必须选中四,另外两张从 {1,2,3}\{1, 2, 3\} 中选,有 (32)=3{3 \choose 2} = 3 种方式。因此概率为 310\dfrac{3}{10}

所以正确答案是 C

The number of ways to choose 33 cards from 55 is (53)=10.{5 \choose 3} = 10. If 44 is the largest value selected, then the other two cards have to be chosen from {1,2,3}.\{1, 2, 3\}. There are (32)=3{3 \choose 2} = 3 ways to do this. The probability is then 310.\dfrac{3}{10}.

Thus, C is the correct answer.

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