2012 AMC 8 第 17 题

先试着解答 2012 AMC 8 第 17 题,然后核对你的答案与视频与精心整理的解答,解答来自 LIVE by Po-Shen Loh。你也可以参加完整限时模拟考试、查看全部 2012 AMC 8 解答,或核对答案。

所有题目均经美国数学协会(MAA)官方合法授权使用。

17.

一个边长为整数的正方形被切成 1010 个正方形,所有小正方形边长都是整数,并且至少 88 个小正方形的面积为 11。原正方形边长的最小可能值是多少?
A square with an integer side length is cut into 1010 squares, all of which have integer side length and at least 88 of which have area 1.1. What is the smallest possible value of the length of the side of the original square?
33
44
55
66
77
答案:B
知识点:铺砖极端原理
小提示:
边长为 33 时,总面积太小,无法切成十个整数边长正方形。
A side length of 33 gives area too small for ten integer squares.
大提示:
一个 44 乘 44 正方形可以按图示方式切分。
A 44 by 44 square can be cut as shown.
视频讲解:
解答视频缩略图
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文字解答:
因为这 1010 个小正方形的边长都是正整数,所以每个小正方形的面积至少为 11,总面积至少为 1010。边长不超过 33 的整数边长正方形面积至多为 32=93^2=9,所以大正方形的边长不能小于 44。
下图把一个 4×44\times4 正方形切成十个整数边长的正方形,其中八个是单位正方形。因此边长 44 可以达到,而且是最小值。
所以正确答案是 B。
Since all 1010 squares have positive integer side lengths, each has area at least 11. Their total area is therefore at least 1010. A square with integer side length at most 33 has area at most 32=93^2=9, so its side length cannot be less than 44.
The following configuration cuts a 4×44\times4 square into ten integer-sided squares, eight of which are unit squares. Therefore side length 44 is attainable and is the minimum.
Thus, the answer is B .
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