2017 AMC 8 第 17 题

先试着解答 2017 AMC 8 第 17 题,然后核对你的答案与视频与精心整理的解答,解答来自 LIVE by Po-Shen Loh。你也可以参加完整限时模拟考试、查看全部 2017 AMC 8 解答,或核对答案

所有题目均经美国数学协会(MAA)官方合法授权使用。

17.

我有一些金币和一些空宝箱。我试着每个宝箱放 99 枚金币,但这样会剩下 22 个宝箱空着。于是我改为每个宝箱放 66 枚金币,但这样会剩下 33 枚金币。我有多少枚金币?

Starting with some gold coins and some empty treasure chests, I tried to put 99 gold coins in each treasure chest, but that left 22 treasure chests empty. So instead I put 66 gold coins in each treasure chest, but then I had 33 gold coins left over. How many gold coins did I have?

99

2727

4545

6363

8181

答案:C
知识点:方程组
难度评级:1240
小提示:

设宝箱数为 nn

Let nn be the number of treasure chests.

大提示:

为每箱 99 枚的尝试和每箱 66 枚的尝试分别写方程

Write one equation for the 99-coins attempt and another for the 66-coins attempt.

视频讲解:
解答视频缩略图
Play video

Click to load, then click again to play

文字解答:

设宝箱数为 nn,金币数为 gg。那么 9(n2)=g 9(n - 2) = g 6n+3=g 6n + 3 = g\text{。}解这个方程组得 n=7n = 7,所以金币数为 67+3=456 \cdot 7 + 3 = 45

所以正确答案是 C

Let nn be the number of treasure chests and gg be the number of gold coins. Then 9(n2)=g9(n - 2) = g and 6n+3=g.6n + 3 = g. Solving this system yields n=7,n = 7, so the number of gold coins is 67+3=45.6 \cdot 7 + 3 = 45.

Thus, C is the correct answer.

第 16 题#16
完整试卷

其他年份的第 17 题

1985 AMC 8 · 1986 AMC 8 · 1987 AMC 8 · 1988 AMC 8 · 1989 AMC 8 · 1990 AMC 8 · 1991 AMC 8 · 1992 AMC 8 · 1993 AMC 8 · 1994 AMC 8 · 1995 AMC 8 · 1996 AMC 8 · 1997 AMC 8 · 1998 AMC 8 · 1999 AMC 8 · 2000 AMC 8 · 2001 AMC 8 · 2002 AMC 8 · 2003 AMC 8 · 2004 AMC 8 · 2005 AMC 8 · 2006 AMC 8 · 2007 AMC 8 · 2008 AMC 8 · 2009 AMC 8 · 2010 AMC 8 · 2011 AMC 8 · 2012 AMC 8 · 2013 AMC 8 · 2014 AMC 8 · 2015 AMC 8 · 2016 AMC 8 · 2018 AMC 8 · 2019 AMC 8 · 2020 AMC 8 · 2022 AMC 8 · 2023 AMC 8 · 2024 AMC 8 · 2025 AMC 8 · 2026 AMC 8