2010 AMC 8 第 21 题

先试着解答 2010 AMC 8 第 21 题,然后核对你的答案与精心整理的解答,解答来自 LIVE by Po-Shen Loh。你也可以参加完整限时模拟考试、查看全部 2010 AMC 8 解答,或核对答案。

所有题目均经美国数学协会(MAA)官方合法授权使用。

21.

惠很爱读书。她买了一本畅销书《数学真美》。第一天,惠读了全书页数的 15\frac{1}{5} 又多读 1212 页;第二天,她读了剩余页数的 14\frac{1}{4} 又多读 1515 页;第三天,她读了剩余页数的 13\frac{1}{3} 又多读 1818 页。随后她发现只剩 6262 页要读,并在次日读完。这本书共有多少页?
Hui is an avid reader. She bought a copy of the bestseller Math is Beautiful. On the first day, Hui read 15\frac{1}{5} of the pages plus 1212 more, and on the second day she read 14\frac{1}{4} of the remaining pages plus 1515 pages. On the third day she read 13\frac{1}{3} of the remaining pages plus 1818 pages. She then realized that there were only 6262 pages left to read, which she read the next day. How many pages are in this book?
 120\ 120
 180\ 180
 240\ 240
 300\ 300
 360\ 360
答案:C
知识点:分数逆推法
小提示:
先倒推额外读的页数,再倒推每天读掉的分数
Undo the extra pages first, then undo the fraction read each day.
大提示:
从第三天后剩下的 6262 页倒推
Work backward from the 6262 pages left after the third day.
解答:
第三天后剩下 6262 页。在读最后额外的 1818 页之前,她还剩 8080 页。这是当时剩余页数的 23\dfrac 23,所以第三天开始前她剩下 120120 页。
在读第二天额外的 1515 页之前,她还剩 120+15=135120+15=135 页。这是当时剩余页数的 34\dfrac 34,所以第二天开始前她剩下 180180 页。
在读第一天额外的 1212 页之前,她还剩 180+12=192180+12=192 页。这是当时剩余页数的 45\dfrac 45,所以第一天开始前她有 240240 页,也就是全书 240240 页。
所以正确答案是 C。
The pages left after the third day is 62.62. Before reading the last 1818 pages, she had 8080 pages left. This is 23\dfrac 23 of the pages remaining, so she had 120120 pages left before the third day.
Before reading the 1515 pages, she had 120+15=135120+15=135 pages left. This is 34\dfrac 34 of the pages remaining, so she had 180180 pages left before the second day.
Before reading the 1212 pages, she had 180+12=192180+12=192 pages left. This is 45\dfrac 45 of the pages remaining, so she had 240240 pages left before the first day, making the book 240240 pages.
Thus, the answer is C .
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