2007 AMC 8 第 23 题

先试着解答 2007 AMC 8 第 23 题,然后核对你的答案与精心整理的解答,解答来自 LIVE by Po-Shen Loh。你也可以参加完整限时模拟考试、查看全部 2007 AMC 8 解答,或核对答案。

所有题目均经美国数学协会(MAA)官方合法授权使用。

23.

图中 5×55 \times 5 方格里的阴影风车形面积是多少?
What is the area of the shaded pinwheel shown in the 5×55 \times 5 grid?
44
66
88
1010
1212
答案:B
知识点:面积分割三角形面积
小提示:
从整个方格中减去未阴影面积更容易
It is easier to subtract the unshaded area from the whole grid.
大提示:
未阴影部分由四个角落正方形和四个全等三角形组成
The unshaded part consists of four corner squares and four congruent triangles.
解答:
可以用总面积减去未阴影面积来求阴影面积。
有 44 个边长为 11 的正方形,每个面积为 11,对未阴影面积贡献共 44。
还有 44 个底为 33、高为 52\dfrac{5}{2} 的三角形,总面积为 4⋅12⋅3⋅52=15。 4 \cdot \dfrac{1}{2} \cdot 3 \cdot \dfrac{5}{2} = 15\text{。}
未阴影总面积为 4+15=194 + 15 = 19。
整个方格面积为 52=255^2 = 25,所以阴影面积为 25−19=625 - 19 = 6。
所以正确答案是 B。
We can find the area of the shaded part by subtracting the area of the unshaded part from the whole area.
There are 44 squares with side length 1,1, contributing 11 each to the unshaded area, for a total of 4.4.
There are also 44 triangles with base 33 and height 52.\dfrac{5}{2}. This contributes a total area of 4⋅12⋅3⋅52=15. 4 \cdot \dfrac{1}{2} \cdot 3 \cdot \dfrac{5}{2} = 15.
The total unshaded area is therefore 4+15=19.4 + 15 = 19.
The total area is 52=25,5^2 = 25, and subtracting the unshaded area yields 25−19=625 - 19 = 6 as the area of the shaded region.
Thus, B is the correct answer.
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