2006 AMC 8 第 12 题

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所有题目均经美国数学协会(MAA)官方合法授权使用。

12.

Antonette 在一场有 1010 道题的测试中得分率为 70%70 \%,在一场有 2020 道题的测试中得分率为 80%80 \%,在一场有 3030 道题的测试中得分率为 90%90 \%。如果三次测试合并成一场有 6060 道题的测试,哪个百分数最接近她的总成绩?

Antonette gets 70%70 \% on a 1010-problem test, 80%80 \% on a 2020-problem test and 90%90 \% on a 3030-problem test. If the three tests are combined into one 6060-problem test, which percent is closest to her overall score?

4040

7777

8080

8383

8787

答案:D
知识点:平均数百分数
难度评级:1100
解答:

Antonette 第一次测试答对 0.710=70.7\cdot 10=7 题。类似地,她第二、三次测试分别答对 0.820=160.8\cdot 20=16 题和 0.930=270.9\cdot 30=27 题。

总共答对 5050 题。合并测试成绩为 1005060=8313%100\cdot \dfrac{50}{60}=83\frac{1}{3}\%,最接近 83%83\%

所以正确答案是 D

Antonette got 0.710=70.7\cdot 10=7 questions right on the first test. Similarly, she got 0.820=160.8\cdot 20=16 and 0.930=270.9\cdot 30=27 problems right on her second and third tests.

Adding these up yields 5050 correct questions. Her score on the combined test would have been 1005060=8313%100\cdot \dfrac{50}{60}=83\frac{1}{3}\%, closest to 83%83\%.

Thus, D is the correct answer.

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