2004 AMC 8 第 4 题

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所有题目均经美国数学协会(MAA)官方合法授权使用。

4.

Hamilton 老师的八年级班想参加一年一度的三人篮球队锦标赛。Lance、Sally、Joy 和 Fred 被选为队员。三名首发队员有多少种选择方式?

Ms. Hamilton’s eighth-grade class wants to participate in the annual three-person-team basketball tournament. Lance, Sally, Joy, and Fred are chosen for the team. In how many ways can the three starters be chosen?

22

44

66

88

1010

答案:B
知识点:组合补集计数
难度评级:660
解答:

若有 33 名首发,则有一人不首发。选择不首发的人就确定了首发。

不首发的人有 44 种选择。

所以正确答案是 B

If there are 33 starters, then one person must not be starting. Choosing the person who doesn't start determines the starters.

There are 44 choices for the person who doesn't start.

Thus, B is the correct answer.

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