2001 AMC 8 第 4 题
先试着解答 2001 AMC 8 第 4 题,然后核对你的答案与精心整理的解答,解答来自 LIVE by Po-Shen Loh。你也可以参加完整限时模拟考试、查看全部 2001 AMC 8 解答,或核对答案。
所有题目均经美国数学协会(MAA)官方合法授权使用。
4.
数字 、、、 和 各使用一次,组成尽可能小的偶数五位数。十位上的数字是
The digits and are each used once to form the smallest possible even five-digit number. The digit in the tens place is
小提示:
这个数必须以 或 结尾
The number must end in or
大提示:
尽量让前面的数字小
Make the earlier digits as small as possible
解答:
个位数字必须是 或 。若个位是 ,把其余数字按尽可能小的顺序排列,得到 。若个位是 ,最小的排列是 ,它更小。因此最小的偶数是 ,其十位数字是 。
所以正确答案是 E。
The units digit must be or . If it is , arranging the remaining digits as small as possible gives . If it is , the smallest arrangement is , which is smaller. Therefore the smallest even number is , whose tens digit is .
Thus, E is the correct answer.
其他年份的第 4 题
- 1985 AMC 8
- 1986 AMC 8
- 1987 AMC 8
- 1988 AMC 8
- 1989 AMC 8
- 1990 AMC 8
- 1991 AMC 8
- 1992 AMC 8
- 1993 AMC 8
- 1994 AMC 8
- 1995 AMC 8
- 1996 AMC 8
- 1997 AMC 8
- 1998 AMC 8
- 1999 AMC 8
- 2000 AMC 8
- 2002 AMC 8
- 2003 AMC 8
- 2004 AMC 8
- 2005 AMC 8
- 2006 AMC 8
- 2007 AMC 8
- 2008 AMC 8
- 2009 AMC 8
- 2010 AMC 8
- 2011 AMC 8
- 2012 AMC 8
- 2013 AMC 8
- 2014 AMC 8
- 2015 AMC 8
- 2016 AMC 8
- 2017 AMC 8
- 2018 AMC 8
- 2019 AMC 8
- 2020 AMC 8
- 2022 AMC 8
- 2023 AMC 8
- 2024 AMC 8
- 2025 AMC 8
- 2026 AMC 8