1999 AMC 8 第 21 题

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所有题目均经美国数学协会(MAA)官方合法授权使用。

21.

AA 的度数是

The degree measure of angle AA is

2020

3030

3535

4040

4545

答案:B
知识点:导角
难度评级:1520
解答:

如下标记顶点。

由补角关系, 同样由补角关系, 利用三角形内角和为 180180^{\circ},得到 再由对顶角相等, 最后在三角形中使用内角和,得到 ABC=180100=80 \angle ABC = 180^{\circ} - 100^{\circ} = 80^{\circ} CED=180110=70 \angle CED = 180^{\circ} - 110^{\circ} = 70^{\circ} ECD=1807040 \angle ECD = 180^{\circ} - 70^{\circ} - 40^{\circ} =70. = 70^{\circ}. ACB=ECD=70. \angle ACB = \angle ECD = 70^{\circ}. A=1808070=30. \angle A = 180^{\circ} - 80^{\circ} - 70^{\circ} = 30^{\circ}.

所以正确答案是 B

Label the vertices as below.

We then have that ABC=180100=80 \angle ABC = 180^{\circ} - 100^{\circ} = 80^{\circ} by supplementary angles. Then we have CED=180110=70 \angle CED = 180^{\circ} - 110^{\circ} = 70^{\circ} again by supplementary angles. Using the sum of the interior angles of a triangle is 180,180^{\circ}, we get ECD=1807040 \angle ECD = 180^{\circ} - 70^{\circ} - 40^{\circ}=70. = 70^{\circ}. Then, using vertical angles, we have ACB=ECD=70. \angle ACB = \angle ECD = 70^{\circ}. Finally, using the sum of the interior angles of a triangle, we get A=1808070=30. \angle A = 180^{\circ} - 80^{\circ} - 70^{\circ} = 30^{\circ}.

Thus, B is the correct answer.

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