1996 AMC 8 第 6 题

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所有题目均经美国数学协会(MAA)官方合法授权使用。

6.

通过下面过程可以得到的最小结果是多少?从集合 {3,5,7,11,13,17}\{3, 5, 7, 11, 13, 17\} 中选择三个不同的数,把其中两个相加,再用它们的和乘以第三个数。

What is the smallest result that can be obtained by the following process? Choose three different numbers from the set {3,5,7,11,13,17}\{3, 5, 7, 11, 13, 17\}, add two of them, then multiply their sum by the third number.

1515

3030

3636

5050

5656

答案:C
知识点:最优化分类讨论
难度评级:820
解答:

使用三个最小的数 3,5,73, 5, 7。可能结果为 3(5+7)=363(5 + 7) = 365(3+7)=505(3 + 7) = 507(3+5)=567(3 + 5) = 56

让最小的数作为乘数得到最小结果 3636

所以正确答案是 C

Use the three smallest numbers 3,5,73, 5, 7. The choices are 3(5+7)=363(5 + 7) = 36, 5(3+7)=505(3 + 7) = 50, and 7(3+5)=567(3 + 5) = 56.

Making the smallest number the multiplier gives the least result, 3636.

Thus, the correct answer is C .

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