Question

任意六个连续正整数的乘积的个位数字是

The unit's digit (one's digit) of the product of any six consecutive positive whole numbers is

$0$

$2$

$4$

$6$

$8$

答案：A

知识点：个位数字整除性

难度评级：730

解答：

任意六个连续正整数中至少包含一个 $5$ 的倍数和一个偶数，所以它们的乘积是 $5 \times 2 = 10$ 的倍数。

$10$ 的倍数个位数字总是 $0$ 。

所以正确答案是 A。

Any six consecutive whole numbers include at least one multiple of $5$ and at least one even number, so their product is a multiple of $5 \times 2 = 10.$

A multiple of $10$ always ends in $0$ .

Thus, the correct answer is A .

1994 AMC 8 第 6 题

答案：A

难度评级：730

解答：

其他年份的第 6 题