1986 AMC 8 第 21 题

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所有题目均经美国数学协会(MAA)官方合法授权使用。

21.

在所示 T 形图中,若把八个带字母的相同正方形中的一个,与四个阴影正方形一起组成图形。所得图形中有多少个可以折成一个没有顶盖的立方体盒子?

Suppose one of the eight lettered identical squares is included with the four shaded squares in the T-shaped figure shown. How many of the resulting figures can be folded into a topless cubical box?

22

33

44

55

66

答案:E
知识点:展开图(立体几何)分类讨论
难度评级:1220
解答:

四个阴影正方形折成开口盒子的四个面,新增正方形提供第五个面。想象折叠过程,正方形 AAEEHHBBDDFF 都能补成一个有效的无顶盒。

正方形 CCGG 不行,因为折叠后会迫使四个面在同一个角相遇。因此有 66 个有效图形。

所以正确答案是 E

The four shaded squares fold into four faces of an open box, and the added square supplies the fifth face. Picturing the folds, the squares A,A, E,E, H,H, B,B, D,D, and FF each complete a valid topless box.

The squares CC and GG do not work, because folding would force four faces to meet at a single corner. That leaves 66 valid figures.

Thus, the correct answer is E .

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