2025 AMC 8 Problem 12

Attempt Problem 12 of the 2025 AMC 8 below, then check your answer against the video solution and professionally curated solution from LIVE by Po-Shen Loh. You can also try the full timed exam, view all 2025 AMC 8 solutions, or check the answer key.

All problems are used with official legal permission of the Mathematical Association of America (MAA).

12.

The region shown below consists of 2424 squares, each with side length 11 centimeter. What is the area, in square centimeters, of the largest circle that can fit inside the region, possibly touching the boundaries?
3π3\pi
4π4\pi
5π5\pi
6π6\pi
8π8\pi
Answer: C
Concepts:circle areaPythagorean Theoremoptimization
Small hint:
The largest circle is centered at the center of the region
Big hint:
Find the distance from the center to the nearest concave corners
Video solution:
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Written solution:
The corners of the region which are closest to the center are the 88 points which lie on this circle:
By the Pythagorean Theorem, each of these points has this distance from the center: 12+22=5. \sqrt{1^2 + 2^2} = \sqrt{5}. The area of the circle is then π(5)2=5π, \pi (\sqrt{5})^2 = 5\pi, which is choice C.
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