1989 AMC 8 Problem 12 — Solution | LIVE by Po-Shen Loh

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1989 AMC 8 Problem 12

Attempt Problem 12 of the 1989 AMC 8 below, then check your answer against the professionally curated solution from LIVE by Po-Shen Loh. You can also try the full timed exam, view all 1989 AMC 8 solutions, or check the answer key.

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12.

What is the value of

$\frac{1 - \frac{1}{3}}{1 - \frac{1}{2}}?$

$\dfrac{1}{3}$

$\dfrac{2}{3}$

$\dfrac{3}{4}$

$\dfrac{3}{2}$

$\dfrac{4}{3}$

Answer: E

Concepts:fraction

Difficulty rating: 770

Solution:

The numerator is $1 - \frac{1}{3} = \frac{2}{3},$ and the denominator is $1 - \frac{1}{2} = \frac{1}{2}.$

Dividing gives $\frac{2}{3} \div \frac{1}{2} = \frac{2}{3} \times 2 = \frac{4}{3}.$

Thus, the correct answer is E .

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