2023 AMC 8 Problem 22

Attempt Problem 22 of the 2023 AMC 8 below, then check your answer against the video solution and professionally curated solution from LIVE by Po-Shen Loh. You can also try the full timed exam, view all 2023 AMC 8 solutions, or check the answer key.

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22.

In a sequence of positive integers, each term after the second is the product of the previous two terms. The sixth term in the sequence is 4000.4000. What is the first term?
11
22
44
55
1010
Answer: D
Concepts:recursionprime factorization
Small hint:
Write the first several terms using first term xx and second term yy
Big hint:
The sixth term is x3y5x^3y^5
Video solution:
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Written solution:
Let xx be the first term and yy be the second.
Then we get the following sequence: x,y,xy,xy2,x2y3,x3y5,⋯ x, y, xy, xy^2, x^2y^3, x^3y^5, \cdots Thus x3y5=4000.x^3y^5 = 4000.
Factoring 4000,4000, gives 4000=25⋅53. 4000 = 2^5 \cdot 5^3. Because xx and yy are positive integers, the only fifth powers that divide 40004000 are 11 and 32.32.
If y=1,y = 1, then x3=4000,x^3 = 4000, which is impossible because 40004000 is not a perfect cube. Therefore, y5=32 y^5 = 32 and y=2. y = 2.
This forces xx to equal 5.5.
Thus, D is the correct answer.
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