2020 AMC 8 Problem 18

Attempt Problem 18 of the 2020 AMC 8 below, then check your answer against the video solution and professionally curated solution from LIVE by Po-Shen Loh. You can also try the full timed exam, view all 2020 AMC 8 solutions, or check the answer key.

All problems are used with official legal permission of the Mathematical Association of America (MAA).

18.

Rectangle ABCDABCD is inscribed in a semicircle with diameter FE‾,\overline{FE}, as shown in the figure. Let DA=16,DA=16, and let FD=AE=9.FD=AE=9. What is the area of ABCD?ABCD?
240240
248248
256256
264264
272272
Answer: A
Concepts:circlePythagorean Theoremrectangle
Small hint:
The diameter is 9+16+99+16+9
Big hint:
Use the radius and half the rectangle base in a right triangle
Video solution:
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Written solution:
Since FEFE is the diameter of the semicircle, we know the length of the diameter is 34,34, and so the radius is 17.17. Let OO be the center of the diameter.
The length from OFOF therefore is 17.17.
Since DD is on OF,OF, we know OD+FD=OFOD+9=17OD=8.\begin{align*} OD + FD &= OF\\ OD + 9 &= 17 \\ OD &= 8. \end{align*}
Also, since we have a semicircle, we know OC=17.OC = 17.
Finally, since ABCDABCD is a rectangle, we know ∠ODC\angle ODC is a right angle. This means we can find DCDC by the Pythagorean Theorem. We know OD2+DC2=OC282+DC2=172DC=15.\begin{align*} OD^2+DC^2&=OC^2 \\ 8^2+DC^2 &= 17^2 \\ DC &= 15. \end{align*}
Thus, the area of the rectangle is DC⋅DA=15⋅16=240.DC\cdot DA = 15\cdot 16=240.
Thus, the correct answer is A.
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