2019 AMC 8 Problem 23

Attempt Problem 23 of the 2019 AMC 8 below, then check your answer against the video solution and professionally curated solution from LIVE by Po-Shen Loh. You can also try the full timed exam, view all 2019 AMC 8 solutions, or check the answer key.

All problems are used with official legal permission of the Mathematical Association of America (MAA).

23.

After Euclid High School’s last basketball game, it was determined that 14\dfrac{1}{4} of the team’s points were scored by Alexa and 27\dfrac{2}{7} were scored by Brittany. Chelsea scored 1515 points. None of the other 77 team members scored more than 22 points. What was the total number of points scored by the other 77 team members?
1010
1111
1212
1313
1414
Answer: B
Concepts:divisibilitylinear equation
Small hint:
The total score must be a multiple of 2828
Big hint:
The other seven players together scored at most 1414
Video solution:
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Written solution:
Let xx be the total number of points and yy be the desired answer.
Then from the problem statement we get that x4+2x7+15+y=x. \dfrac{x}{4} + \dfrac{2x}{7} + 15 + y = x.
Simplifying yields y+15=13x28. y + 15 = \dfrac{13x}{28}.
We know that y≤14y \leq 14 since none of the 77 team members scored more than 22 points.
We also know that xx must be a multiple of 28.28. If x=28,x = 28, then we get that y+15=13⇒y=−2, y + 15 = 13 \Rightarrow y = -2, which is not allowed.
If x=2⋅28=56,x = 2 \cdot 28 = 56, then we have that y+15=26⇒y=11, y + 15 = 26 \Rightarrow y = 11, which works.
The next possible total is x=84,x = 84, which would give y=24>14.y = 24 > 14. Every larger multiple of 2828 makes yy still larger, so y=11y = 11 is the only possible value.
Thus, the correct answer is B.
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