2016 AMC 8 Problem 11

Attempt Problem 11 of the 2016 AMC 8 below, then check your answer against the video solution and professionally curated solution from LIVE by Po-Shen Loh. You can also try the full timed exam, view all 2016 AMC 8 solutions, or check the answer key.

All problems are used with official legal permission of the Mathematical Association of America (MAA).

11.

Determine how many two-digit numbers satisfy the following property:
When the number is added to the number obtained by reversing its digits, the sum is 132.132.
5 5
7 7
9 9
11 11
12 12
Answer: B
Concepts:digitsplace value
Small hint:
Write the two-digit number as 10a+b10a+b.
Big hint:
Adding the reversed number gives 11(a+b)11(a+b).
Video solution:
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Written solution:
Let aa be the tens digit and bb the units digit. Adding the number and its reversal gives (10a+b)+(10b+a)=13211(a+b)=132,\begin{aligned} (10a+b)+(10b+a)&=132\\ 11(a+b)&=132, \end{aligned} so a+b=12a+b=12. The valid digit pairs are (3,9),(3,9), (4,8),(4,8), (5,7),(5,7), (6,6),(6,6), (7,5),(7,5), (8,4),(8,4), (9,3),(9,3), giving 77 numbers.
Thus, B is the correct answer.
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