2012 AMC 8 Problem 11

Below is the video solution and professionally curated solution for Problem 11 of the 2012 AMC 8, from LIVE by Po-Shen Loh. You can also try the full timed exam, view all 2012 AMC 8 solutions, or check the answer key.

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Concepts:meanmedian (data)mode

Difficulty rating: 1240

11.

The mean, median, and unique mode of the positive integers 3,4,5,6,6,7,3, 4, 5, 6, 6, 7, and xx are all equal. What is the value of x?x?

5 5

6 6

7 7

11 11

12 12

Video solution:
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Written solution:

Every listed value except 66 appears once while 66 appears twice. If any of the other values are chosen, then we have two modes, which means we do not have a unique mode. Otherwise, the only value that shows up more than once is 66 making that the unique mode. This also means 66 is the mean. Since there are 77 elements, the sum of the elements is 67=42.6\cdot 7 = 42. The sum is also 3+4+5+6+6+7+x3+4+5+6+6+7+x =31+x= 31+x =42,= 42, so x=11.x = 11.

Thus, the answer is D .

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