2013 AMC 8 Problem 5
Attempt Problem 5 of the 2013 AMC 8 below, then check your answer against the video solution and professionally curated solution from LIVE by Po-Shen Loh. You can also try the full timed exam, view all 2013 AMC 8 solutions, or check the answer key.
All problems are used with official legal permission of the Mathematical Association of America (MAA).
5.
Hammie is in the th grade and weighs pounds. His quadruplet sisters are tiny babies and weigh and pounds. Which is greater, the average (mean) weight of these five children or the median weight, and by how many pounds?
median, by
median, by
average, by
average, by
average, by
Answer: E
Small hint:
Order the five weights before finding the median.
Big hint:
Compare the median with the total weight divided by .
Video solution:
Click to load, then click again to play
Written solution:
The median weight is the middle value, which we can find as: Therefore, the median is pounds.
The average (mean) can be calculated to be: This is greater than the median, specifically, the mean is pounds greater than the median.
Thus, E is the correct answer.
Problem 5 in other years
- 1985 AMC 8
- 1986 AMC 8
- 1987 AMC 8
- 1988 AMC 8
- 1989 AMC 8
- 1990 AMC 8
- 1991 AMC 8
- 1992 AMC 8
- 1993 AMC 8
- 1994 AMC 8
- 1995 AMC 8
- 1996 AMC 8
- 1997 AMC 8
- 1998 AMC 8
- 1999 AMC 8
- 2000 AMC 8
- 2001 AMC 8
- 2002 AMC 8
- 2003 AMC 8
- 2004 AMC 8
- 2005 AMC 8
- 2006 AMC 8
- 2007 AMC 8
- 2008 AMC 8
- 2009 AMC 8
- 2010 AMC 8
- 2011 AMC 8
- 2012 AMC 8
- 2014 AMC 8
- 2015 AMC 8
- 2016 AMC 8
- 2017 AMC 8
- 2018 AMC 8
- 2019 AMC 8
- 2020 AMC 8
- 2022 AMC 8
- 2023 AMC 8
- 2024 AMC 8
- 2025 AMC 8
- 2026 AMC 8