2013 AMC 8 Problem 20

Attempt Problem 20 of the 2013 AMC 8 below, then check your answer against the video solution and professionally curated solution from LIVE by Po-Shen Loh. You can also try the full timed exam, view all 2013 AMC 8 solutions, or check the answer key.

All problems are used with official legal permission of the Mathematical Association of America (MAA).

20.

A 1×21 \times 2 rectangle is inscribed in a semicircle with the longer side on the diameter. What is the area of the semicircle?
π2\dfrac{\pi}{2}
2π3\dfrac{2\pi}{3}
π\pi
4π3\dfrac{4\pi}{3}
5π3\dfrac{5\pi}{3}
Answer: C
Concepts:Pythagorean Theoremcircle area
Small hint:
The radius goes from the midpoint of the diameter to a top corner of the rectangle.
Big hint:
That radius is the hypotenuse of a 11 by 11 right triangle.
Video solution:
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Written solution:
Using the Pythagorean theorem, we get that the radius of the semicircle is 2.\sqrt{2}. This means that the area of the semicircle is 12⋅π⋅22=π.\dfrac{1}{2} \cdot \pi \cdot \sqrt{2}^2 = \pi. Thus, C is the correct answer.
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