2013 AMC 8 Problem 14
Attempt Problem 14 of the 2013 AMC 8 below, then check your answer against the video solution and professionally curated solution from LIVE by Po-Shen Loh. You can also try the full timed exam, view all 2013 AMC 8 solutions, or check the answer key.
All problems are used with official legal permission of the Mathematical Association of America (MAA).
14.
Abe holds green and red jelly bean in his hand. Bea holds green, yellow, and red jelly beans in her hand. Each randomly picks a jelly bean to show the other. What is the probability that the colors match?
Answer: C
Small hint:
There are equally likely jelly-bean pairings.
Big hint:
Count the green match and the two red matches.
Video solution:
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Written solution:
There are equally likely ways for Abe and Bea to choose their jelly beans. The colors match if they both choose green, which can happen in way, or if they both choose red, which can happen in ways.
Thus of the outcomes match, for probability .
Thus, C is the correct answer.
Problem 14 in other years
- 1985 AMC 8
- 1986 AMC 8
- 1987 AMC 8
- 1988 AMC 8
- 1989 AMC 8
- 1990 AMC 8
- 1991 AMC 8
- 1992 AMC 8
- 1993 AMC 8
- 1994 AMC 8
- 1995 AMC 8
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- 1997 AMC 8
- 1998 AMC 8
- 1999 AMC 8
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