1994 AMC 8 Problem 14

Below is the professionally curated solution for Problem 14 of the 1994 AMC 8, from LIVE by Po-Shen Loh. You can also try the full timed exam, view all 1994 AMC 8 solutions, or check the answer key.

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Concepts:rate

Difficulty rating: 820

14.

Two children at a time can play pairball. For 9090 minutes, with only two children playing at one time, five children take turns so that each one plays the same amount of time. The number of minutes each child plays is

99

1010

1818

2020

3636

Solution:

Two children play at every moment for 9090 minutes, so the total playing time is 2×90=1802 \times 90 = 180 child-minutes.

Split equally among 55 children, each plays 1805=36\dfrac{180}{5} = 36 minutes.

Thus, the correct answer is E .

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