2012 AMC 8 Problem 10

Attempt Problem 10 of the 2012 AMC 8 below, then check your answer against the video solution and professionally curated solution from LIVE by Po-Shen Loh. You can also try the full timed exam, view all 2012 AMC 8 solutions, or check the answer key.

All problems are used with official legal permission of the Mathematical Association of America (MAA).

10.

How many 44-digit numbers greater than 10001000 are there that use the four digits of 2012?2012?
6 6
7 7
8 8
9 9
12 12
Answer: D
Concepts:multiset permutations
Small hint:
The first digit cannot be 00.
Big hint:
Count arrangements starting with 11, then arrangements starting with 22.
Video solution:
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Written solution:
First, we can’t have the 00 in the thousands position. Therefore, we have 33 spots we can put it. Then, we have 33 available positions for the 1,1, and then the two 22s are placed. This makes it such that we have 3⋅3=93\cdot 3 = 9 combinations.
Thus, the answer is D .
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