2019 AMC 8 Problem 10

Below is the video solution and professionally curated solution for Problem 10 of the 2019 AMC 8, from LIVE by Po-Shen Loh. You can also try the full timed exam, view all 2019 AMC 8 solutions, or check the answer key.

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Concepts:meanmedian (data)

Difficulty rating: 1020

10.

The diagram shows the number of students at soccer practice each weekday during last week. After computing the mean and median values, Coach discovers that there were actually 2121 participants on Wednesday. Which of the following statements describes the change in the mean and median after the correction is made?

The mean increases by 11 and the median does not change.

The mean increases by 11 and the median increases by 1.1.

The mean increases by 11 and the median increases by 5.5.

The mean increases by 55 and the median increases by 1.1.

The mean increases by 55 and the median increases by 5.5.

Video solution:
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Written solution:

There are 55 more participants, which means the mean is increased by 5÷5=1.5 \div 5 = 1.

Right now, we can see that the median is 20.20. If 1616 gets replaced with 21,21, then the median becomes 21.21.

This shows that the median is also increased by 1.1.

Thus, the correct answer is B.

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