2011 AMC 8 Problem 4

Attempt Problem 4 of the 2011 AMC 8 below, then check your answer against the professionally curated solution from LIVE by Po-Shen Loh. You can also try the full timed exam, view all 2011 AMC 8 solutions, or check the answer key.

All problems are used with official legal permission of the Mathematical Association of America (MAA).

4.

Here is a list of the numbers of fish that Tyler caught in nine outings last summer: 2,0,1,3,0,3,3,1,2.2,0,1,3,0,3,3,1,2. Which statement about the mean, median, and mode is true?

median < mean < mode

mean < mode < median

mean < median < mode

median < mode < mean

mode < median < mean

Answer: C
Concepts:meanmedian (data)mode
Difficulty rating: 720
Solution:

To find these values more easily, we can get the following ordered list: 0,0,1,1,2,2,3,3,3. 0, 0, 1, 1, 2, 2, 3, 3, 3.

From this, we see that the mode is 3,3, the median is 2,2, and the mean is 15/9=5/3.15 / 9 = 5 / 3.

Since 53<2<3,\dfrac{5}{3} < 2 < 3, we get that:

mean << median << mode.

Thus, C is the correct answer.

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