2011 AMC 8 Problem 4

Attempt Problem 4 of the 2011 AMC 8 below, then check your answer against the professionally curated solution from LIVE by Po-Shen Loh. You can also try the full timed exam, view all 2011 AMC 8 solutions, or check the answer key.

All problems are used with official legal permission of the Mathematical Association of America (MAA).

4.

Here is a list of the numbers of fish that Tyler caught in nine outings last summer: 2,0,1,3,0,3,3,1,2.2,0,1,3,0,3,3,1,2. Which statement about the mean, mode, and median of these numbers is true?
median <\lt mean <\lt mode
mean <\lt mode <\lt median
mean <\lt median <\lt mode
median <\lt mode <\lt mean
mode <\lt median <\lt mean
Answer: C
Concepts:meanmedian (data)mode
Small hint:
The mean is the total number of fish divided by 99.
Big hint:
Order the nine numbers before finding the median and mode.
Solution:
To find these values more easily, we can get the following ordered list: 0,0,1,1,2,2,3,3,3. 0, 0, 1, 1, 2, 2, 3, 3, 3.
From this, we see that the mode is 3,3, the median is 2,2, and the mean is 159=53.\frac{15}{9} = \frac{5}{3}.
Since 53<2<3,\dfrac{5}{3} < 2 < 3, we get that:
mean << median << mode.
Thus, C is the correct answer.
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