2011 AMC 8 Problem 11

Attempt Problem 11 of the 2011 AMC 8 below, then check your answer against the professionally curated solution from LIVE by Po-Shen Loh. You can also try the full timed exam, view all 2011 AMC 8 solutions, or check the answer key.

All problems are used with official legal permission of the Mathematical Association of America (MAA).

11.

The graph shows the number of minutes studied by both Asha (left bar) and Sasha (right bar) in one week. On the average, how many more minutes per day did Sasha study than Asha?
66
88
99
1010
1212
Answer: A
Concepts:data and graph interpretationmean
Small hint:
Average the five daily differences instead of averaging each person separately.
Big hint:
Compare Sasha and Asha day by day.
Solution:
We can calculate the difference in average minutes by looking at the differences per day.
Starting with Monday, the differences between Sasha and Asha are 10,10, −10,-10, 20,20, 30,30, and −20.-20. This is a total of 3030 minutes. Therefore, the average difference is 30÷5=6.30 \div 5 = 6.
Thus, A is the correct answer.
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