2010 AMC 8 Problem 23

Attempt Problem 23 of the 2010 AMC 8 below, then check your answer against the professionally curated solution from LIVE by Po-Shen Loh. You can also try the full timed exam, view all 2010 AMC 8 solutions, or check the answer key.

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23.

Semicircles POQPOQ and ROSROS pass through the center of circle O.O. What is the ratio of the combined areas of the two semicircles to the area of circle O?O?
24 \dfrac{\sqrt 2}{4}
12 \dfrac{1}{2}
2π \dfrac{2}{\pi}
23 \dfrac{2}{3}
22 \dfrac{\sqrt 2}{2}
Answer: B
Concepts:circle areaPythagorean Theoremarea ratio
Small hint:
The two semicircles together have the area of one circle of radius 11.
Big hint:
Find the radius of circle OO from the coordinates.
Solution:
The area of each of the semicircles is πr22.\pi \dfrac {r^2}{2} . Each of them has a radius of 1,1, so their combined area is π12+π12=π.\pi \frac{1}{2} + \pi \frac 12 = \pi.
Next, the radius of the larger circle is equal to the length of OQ,OQ, which is equal to 12+12=2. \sqrt{1^2+1^2} = \sqrt 2. Its area is πr2=π(2)2=2π.\pi r^2 = \pi(\sqrt{2})^2 = 2\pi.
This means the ratio is π2π=12.\dfrac{\pi}{2\pi} = \frac 12.
Thus, the answer is B .
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