2010 AMC 8 Problem 11

Attempt Problem 11 of the 2010 AMC 8 below, then check your answer against the professionally curated solution from LIVE by Po-Shen Loh. You can also try the full timed exam, view all 2010 AMC 8 solutions, or check the answer key.

All problems are used with official legal permission of the Mathematical Association of America (MAA).

11.

The top of one tree is 1616 feet higher than the top of another tree. The heights of the two trees are in the ratio 3:4.3:4. In feet, how tall is the taller tree?
 48 \ 48
 64 \ 64
 80 \ 80
 96 \ 96
 112 \ 112
Answer: B
Concepts:ratio and proportionlinear equation
Small hint:
The taller tree has four of those equal parts.
Big hint:
The ratio 3:43:4 means the height difference is one ratio part.
Solution:
Let b,b, ss be the heights of bigger and smaller trees respectively. Then, b=s+16b= s+16 and s=0.75b. s = 0.75b. If we substitute, we get b=0.75b+16  ⟹  0.25b=16b = 0.75b + 16 \implies 0.25b = 16   ⟹  b=64.\implies b = 64.
Thus, the answer is B .
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