2009 AMC 8 Problem 5

Attempt Problem 5 of the 2009 AMC 8 below, then check your answer against the professionally curated solution from LIVE by Po-Shen Loh. You can also try the full timed exam, view all 2009 AMC 8 solutions, or check the answer key.

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5.

A sequence of numbers starts with 1,1, 2,2, and 3.3. The fourth number of the sequence is the sum of the previous three numbers in the sequence: 1+2+3=6.1 + 2 + 3 = 6. In the same way, every number after the fourth is the sum of the previous three numbers. What is the eighth number in the sequence?

1111

2020

3737

6868

9999

Answer: D
Concepts:recursion
Difficulty rating: 770
Solution:

The sequence begins 1,2,31,2,3.

The next terms are 1+2+3=61+2+3=6, 2+3+6=112+3+6=11, 3+6+11=203+6+11=20, 6+11+20=376+11+20=37, and 11+20+37=6811+20+37=68.

Thus, D is the correct answer.

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