2009 AMC 8 Problem 20

Attempt Problem 20 of the 2009 AMC 8 below, then check your answer against the professionally curated solution from LIVE by Po-Shen Loh. You can also try the full timed exam, view all 2009 AMC 8 solutions, or check the answer key.

All problems are used with official legal permission of the Mathematical Association of America (MAA).

20.

How many non-congruent triangles have vertices at three of the eight points in the array shown below?
55
66
77
88
99
Answer: D
Concepts:congruence (geometry)systematic listingsymmetry
Small hint:
Use symmetry to avoid counting every triangle separately.
Big hint:
Classify triangles by their side lengths after choosing vertices from the two-row array.
Solution:
By symmetry, it is enough to list one representative of each possible triangle shape.
One complete list of non-congruent possibilities is ABE,ABE, ABG,ABG, ACE,ACE, ABH,ABH, AEH,AEH, ACF,ACF, ACH,ACH, and ADF.ADF.
Every other triangle formed from the eight points is congruent to one of these 88 triangles.
Thus, D is the correct answer.
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