2009 AMC 8 Problem 11

Attempt Problem 11 of the 2009 AMC 8 below, then check your answer against the professionally curated solution from LIVE by Po-Shen Loh. You can also try the full timed exam, view all 2009 AMC 8 solutions, or check the answer key.

All problems are used with official legal permission of the Mathematical Association of America (MAA).

11.

The Amaco Middle School bookstore sells pencils costing a whole number of cents. Some seventh graders each bought a pencil, paying a total of 1.431.43 dollars. Some of the 3030 sixth graders each bought a pencil, and they paid a total of 1.951.95 dollars. How many more sixth graders than seventh graders bought a pencil?
11
22
33
44
55
Answer: D
Concepts:greatest common divisorprime factorization
Small hint:
The pencil price must divide both total costs in cents.
Big hint:
Use the fact that at most 3030 sixth graders bought pencils to rule out a 11-cent price.
Solution:
The number of seventh graders that bought a pencil is 143143 divided by the price of a pencil. Similarly, the number of sixth graders that bought a pencil is 195195 divided by the price of a pencil.
This means that the price of a pencil divides both 143143 and 195.195. Prime factorizing, we get 143=11⋅13 143 = 11 \cdot 13 and 195=3⋅5⋅13. 195 = 3 \cdot 5 \cdot 13. The only numbers that divide both 143143 and 195195 are 11 and 13.13.
If 11 cent was the price of the pencil, that means 195195 sixth graders bought pencils, which is not possible. Therefore, the price of a pencil is 1313 cents.
This means that 143÷13=11143 \div 13 = 11 seventh graders bought a pencil, and 195÷13=15195 \div 13 = 15 sixth graders bought a pencil. Therefore, 44 more sixth graders than seventh graders bought pencils.
Thus, D is the correct answer.
LIVE by Po-Shen Loh
Programs

LIVE Classes

Self-Paced Classes

Stars

Scholarship

About Us

Who Is Po-Shen Loh?

Email Contact

Newsletter

Jobs

Become a Star

For a more Thought Full world.

© 2026 Expii, Inc.