2007 AMC 8 Problem 11
Attempt Problem 11 of the 2007 AMC 8 below, then check your answer against the professionally curated solution from LIVE by Po-Shen Loh. You can also try the full timed exam, view all 2007 AMC 8 solutions, or check the answer key.
All problems are used with official legal permission of the Mathematical Association of America (MAA).
11.
Tiles and are translated so one tile coincides with each of the rectangles and In the final arrangement, the two numbers on any side common to two adjacent tiles must be the same. Which of the tiles is translated to Rectangle
cannot be determined
Answer: D
Small hint:
Look for edge numbers that appear on only one tile.
Big hint:
The and force the placement of Tile before deciding which tile is in .
Solution:
Only Tile has a on an edge, so Tile must be placed in or , where that edge can be on the outside.
Tile also has a on its right edge, and no other tile has a . Therefore Tile must be placed in , with its on the outside.
The only tile that can match the on the left edge of Tile is Tile , so Tile is placed in .
Thus, D is the correct answer.
Problem 11 in other years
- 1985 AMC 8
- 1986 AMC 8
- 1987 AMC 8
- 1988 AMC 8
- 1989 AMC 8
- 1990 AMC 8
- 1991 AMC 8
- 1992 AMC 8
- 1993 AMC 8
- 1994 AMC 8
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- 1998 AMC 8
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