2006 AMC 8 Problem 17
Attempt Problem 17 of the 2006 AMC 8 below, then check your answer against the professionally curated solution from LIVE by Po-Shen Loh. You can also try the full timed exam, view all 2006 AMC 8 solutions, or check the answer key.
All problems are used with official legal permission of the Mathematical Association of America (MAA).
17.
Jeff rotates spinners and and adds the resulting numbers. What is the probability that his sum is an odd number?
Answer: B
Small hint:
Track only odd and even values, not the exact sums.
Big hint:
Spinner always gives an even number, and spinner always gives an odd number.
Solution:
Spinner always lands on an even number, so it does not change the parity of the total. Spinner always lands on an odd number.
For the full sum to be odd, the number from spinner must be even. Only one of the three equal sectors of spinner contains an even number.
Therefore the probability is .
Thus, B is the correct answer.
Problem 17 in other years
- 1985 AMC 8
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