2006 AMC 8 Problem 12

Attempt Problem 12 of the 2006 AMC 8 below, then check your answer against the professionally curated solution from LIVE by Po-Shen Loh. You can also try the full timed exam, view all 2006 AMC 8 solutions, or check the answer key.

All problems are used with official legal permission of the Mathematical Association of America (MAA).

12.

Antonette gets 70%70 \% on a 1010-problem test, 80%80 \% on a 2020-problem test and 90%90 \% on a 3030-problem test. If the three tests are combined into one 6060-problem test, which percent is closest to her overall score?
4040
7777
8080
8383
8787
Answer: D
Concepts:meanpercentage
Small hint:
Convert each test percentage into a number of correct answers.
Big hint:
This is a weighted average by number of problems, not a plain average of the three percentages.
Solution:
Antonette got 0.7⋅10=70.7\cdot 10=7 questions right on the first test. Similarly, she got 0.8⋅20=160.8\cdot 20=16 and 0.9⋅30=270.9\cdot 30=27 problems right on her second and third tests.
Adding these up yields 5050 correct questions. Her score on the combined test would have been 100⋅5060=8313%100\cdot \dfrac{50}{60}=83\frac{1}{3}\%, closest to 83%83\%.
Thus, D is the correct answer.
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