2005 AMC 8 Problem 14

Attempt Problem 14 of the 2005 AMC 8 below, then check your answer against the professionally curated solution from LIVE by Po-Shen Loh. You can also try the full timed exam, view all 2005 AMC 8 solutions, or check the answer key.

All problems are used with official legal permission of the Mathematical Association of America (MAA).

14.

The Little Twelve Basketball Conference has two divisions, with six teams in each division. Each team plays each of the other teams in its own division twice and every team in the other division once. How many conference games are scheduled?
8080
9696
100100
108108
192192
Answer: B
Concepts:double countingbasic counting
Small hint:
Count each team’s games, then correct for double-counting.
Big hint:
Each game is counted once for each of its two teams.
Solution:
Let us focus on one team. This team plays against 55 other teams twice in its own division, for a total of 2⋅5=102 \cdot 5 = 10 games.
This team also plays 66 games with teams from the other division. Therefore, they play a total of 10+6=1610 + 6 = 16 games.
There are 1212 teams total, so there are 12⋅16=19212 \cdot 16 = 192 games conducted. Each game, however, involves 22 teams, so we have to divide by 2.2.
This gives us the actual total number of games to be 192÷2=96.192 \div 2 = 96.
Thus, B is the correct answer.
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