2005 AMC 8 Problem 10

Attempt Problem 10 of the 2005 AMC 8 below, then check your answer against the professionally curated solution from LIVE by Po-Shen Loh. You can also try the full timed exam, view all 2005 AMC 8 solutions, or check the answer key.

All problems are used with official legal permission of the Mathematical Association of America (MAA).

10.

Joe had walked half way from home to school when he realized he was late. He ran the rest of the way to school. He ran 33 times as fast as he walked. Joe took 66 minutes to walk half way to school. How many minutes did it take Joe to get from home to school?
77
7.37.3
7.77.7
88
8.38.3
Answer: D
Concepts:distance rate and timeratio and proportion
Small hint:
Joe runs the same half-distance he previously walked.
Big hint:
Running three times as fast takes one third as much time.
Solution:
Joe took 66 minutes to walk the first half of the distance.
He ran the second half, the same distance, at 33 times his walking speed, so that half took 6÷3=26\div3=2 minutes.
His total time was 6+2=86+2=8 minutes.
Thus, D is the correct answer.
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