Question

A board game spinner is divided into three regions labeled $A,$ $B$ and $C.$ The probability of the arrow stopping on region $A$ is $\frac{1}{3}$ and on region $B$ is $\frac{1}{2}.$ The probability of the arrow stopping on region $C$ is

$\dfrac{1}{12}$

$\dfrac{1}{6}$

$\dfrac{1}{5}$

$\dfrac{1}{3}$

$\dfrac{2}{5}$

Answer: B

Concepts:basic probability complementary probability

Difficulty rating: 1090

Solution:

The total probability is $1.$ We need to subtract the probability of the spinner landing on $B$ and $A$ to get $C,$ which is $1 - \dfrac{1}{3} - \dfrac{1}{2} = \dfrac{1}{6}.$

Thus, B is the correct answer.

2002 AMC 8 Problem 12

Answer: B

Difficulty rating: 1090

Solution:

Problem 12 in Other Years