1996 AMC 8 Problem 20

Attempt Problem 20 of the 1996 AMC 8 below, then check your answer against the professionally curated solution from LIVE by Po-Shen Loh. You can also try the full timed exam, view all 1996 AMC 8 solutions, or check the answer key.

All problems are used with official legal permission of the Mathematical Association of America (MAA).

20.

Suppose there is a special key on a calculator that replaces the number xx currently displayed with the number given by the formula 11−x.\frac{1}{1 - x}. For example, if the calculator is displaying 22 and the special key is pressed, then the calculator will display −1-1 since 11−2=−1.\frac{1}{1 - 2} = -1. Now suppose that the calculator is displaying 5.5. After the special key is pressed 100100 times in a row, the calculator will display
−0.25-0.25
00
0.80.8
1.251.25
55
Answer: A
Concepts:functionmodular arithmetic
Small hint:
Apply the key a few times starting from 55 and watch for a repeating cycle
Big hint:
The values cycle with period 3;3; find where 100100 lands in the cycle
Solution:
Starting from 5:5: 11−5=−0.25,\frac{1}{1 - 5} = -0.25, then 11+0.25=0.8,\frac{1}{1 + 0.25} = 0.8, then 11−0.8=5.\frac{1}{1 - 0.8} = 5. The values repeat with period 3.3.
Since 100=3⋅33+1,100 = 3 \cdot 33 + 1, the 100100th press gives the same result as the first press, −0.25.-0.25.
Thus, the correct answer is A .
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