1995 AMC 8 Problem 23
Attempt Problem 23 of the 1995 AMC 8 below, then check your answer against the professionally curated solution from LIVE by Po-Shen Loh. You can also try the full timed exam, view all 1995 AMC 8 solutions, or check the answer key.
All problems are used with official legal permission of the Mathematical Association of America (MAA).
23.
How many four-digit whole numbers are there such that the leftmost digit is odd, the second digit is even, and all four digits are different?
Answer: B
Solution:
The first digit is odd: choices. The second is even: choices (none of which repeats the odd first digit).
The third digit is any of the unused digits, and the fourth is any of the remaining. In total,
Thus, the correct answer is B .
Problem 23 in Other Years
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