1994 AMC 8 Problem 20
Attempt Problem 20 of the 1994 AMC 8 below, then check your answer against the professionally curated solution from LIVE by Po-Shen Loh. You can also try the full timed exam, view all 1994 AMC 8 solutions, or check the answer key.
All problems are used with official legal permission of the Mathematical Association of America (MAA).
20.
Let and be four different digits selected from the set
If the sum is to be as small as possible, then must equal
Answer: D
Small hint:
To make each fraction small, use the smallest digits as numerators and the largest as denominators
Big hint:
Compare with to see which is smaller
Solution:
Small numerators and large denominators make small fractions, so use and as numerators and and as denominators.
Pairing the larger numerator with the larger denominator gives which is smaller than So the minimum sum is
Thus, the correct answer is D .
Problem 20 in other years
- 1985 AMC 8
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