1994 AMC 8 Problem 13 — Solution | LIVE by Po-Shen Loh

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1994 AMC 8 Problem 13

Attempt Problem 13 of the 1994 AMC 8 below, then check your answer against the professionally curated solution from LIVE by Po-Shen Loh. You can also try the full timed exam, view all 1994 AMC 8 solutions, or check the answer key.

All problems are used with official legal permission of the Mathematical Association of America (MAA).

13.

The number halfway between $\dfrac{1}{6}$ and $\dfrac{1}{4}$ is

$\dfrac{1}{10}$

$\dfrac{1}{5}$

$\dfrac{5}{24}$

$\dfrac{7}{24}$

$\dfrac{5}{12}$

Answer: C

Concepts:mean fraction

Difficulty rating: 660

Solution:

The number halfway between two values is their average: $\dfrac{\frac16 + \frac14}{2}.$

Since $\dfrac16 + \dfrac14 = \dfrac{2}{12} + \dfrac{3}{12} = \dfrac{5}{12},$ the average is $\dfrac{5}{12} \div 2 = \dfrac{5}{24}.$

Thus, the correct answer is C .

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